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All of this while Excel is still stuck in 1997 in terms of functionality.

Hm?

Proof that high resolutions do not exist? Huh, did not see that one coming.

Proof for what is the question.

Big fan here, I like it.

I do not understand you. So many things have no inherent value but still cost arbitrarily much?

…so?

So the point is that always only exactly 2 elements are compared and so you first have to split everything into groups of 2. Seems very inefficient for larger datasets, since you need to handle every single item over and over again and compare so so often. But not a sorting and comparison expert, so no idea if human sorting logic applies at all.

How does the last step sort an of the sizes? Why even have all the other steps if that one can do it all?

I do not pay respect to sad stuff usually?

?

It is not direct sunlight that is melting your ice mate. Let’s say the scoop has 10 cm² getting blasted from the sun, that’s 1 Watt of heat under maximum possible conditions (Sun vertically above you, perfectly black ice, etc.). tl;dr: In total from convenction 1.8 W, condensation 2.5 W and radiation 0.65 W = 4.95 W -> maximum possible sunlight on earth would only increase this by 20 %, more realistic sunlight something like 10 %.

Actual math: Compare that to ambient temperatures of say, 30 °C, and let’s again say 10 cm² cross section, which translates to a diameter of 3.57 cm, so a sphere with a surface of 40 cm². The heat transfer coefficient under normal conditions is about 15 W/(m²K), so we get: 15 W/(m²K) * 0.004 m² * 30 K = 1.8 W

Additionally, we have latent heat from water (humidity) condensing on the cold surface: Let’s assume a Schmidt number of 0.6, so we get a mass transfer coefficient of: 15 W/(m²K) / [1.2 kg/m³ * 1000 J/(kgK)] * 0.6^(-2/3) = 0.0176 m/s Specific gas constant: 8.314 J/(molK) / 0.018 kg/mol = 462 J/(kgK) So the mass flux (condensation speed) is: 0.0176 m/s * 2000 Pa / [462 J/(kgK) * 273 K] = 0.00038 kg/(m²s)

Given the heat of condensation of 2257 kJ/kg water we thus get: 0.00038 kg/(m²*s) * 2257000 J/kg = 632 W/m²

And thus for our little sphere: 632 W/m² * 0.004 m² = 2.5 W

… Then we also have radiation from the hot surrounding, let’s assume 30 °C again, we get: Q = 5.67E-8 W/(m²*K^4) * 0.004 m² * (303 K^4 - 273 K^4) = 0.65 W (omitting radiation from the sky)

Why is your shaker crying? Terrible design.

How does it compare to matplotlib?

Any number that I write down is a number. I am not writing novels, the numbers I write down are supposed to be easy you find. You look through the document to find numbers, that is easy to do.

You can vote without having 70 % of your feed filled with the fucked up USA politics.

Well for 750 mega liters that seems like a reasonable price. About 28 m³ per unit of money! Buy buy buy!

I’m the 1970s 70% owned their homes by age 35. But it is still above 50 % today, not as dramatic as I assumed when I just looked up the numbers.

Correct. Author must be close-ish to a cat.